Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day = [tex]\frac{14000}{30} = \frac{1400}{3}[/tex] lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) = [tex]\frac{1400}{3} \times 16=\frac{22400}{3}[/tex] oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat = [tex]\frac{22400}{3} \div 3.4 = 2196[/tex] fish
Thus, the killer whale needs to eat 2196 fish.
