Determine the mass of each of the following:
(a)0.0146 mol KOH
(b)10.2 mol etane, C2H6
(c)1.6 x 10-3 mol Na2SO4
(d)6.854 x 103 mol glucose, C6 H12 O6
(e)2.86 mol Co(NH3)6 Cl3

Respuesta :

Answer:

A) 0.82 g

B) 306 g

C) 0.23 g

D) [tex]1.261x10^{6}[/tex] g

E) 764 g

Explanation:

A) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol K=39.10 O=16.00

By adding the masses of the atoms in a molecule, we get its molecular weight.

KOH molecular mass is 1.00+39.10+16 = 56.10 g/mol

 Therefore the mass in 0.0146 mol of KOH is:

56.10 g/mol x 0.0146 mol = 0.82 g

B) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol C=12.01

By adding the masses of the atoms in a molecule, we get its molecular weight.

C2H6 molecular mass is 6x1.00+2x12.01= 30.02 g/mol

 Therefore the mass in 10.2 mol of KOH is:

30.02 g/mol x 10.2 mol = 306 g

C) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

Na=22.99 g/mol S=32.07 O=16.00

By adding the masses of the atoms in a molecule, we get its molecular weight.

Na2SO4 molecular mass is 2x22.99+32.07+4x16.00=142.05 g/mol

 Therefore the mass in 0.0016 mol of Na2SO4  is:

142.05 g/mol x 0.0016 mol = 0.23 g

D) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol C=12.01  O=16.00

By adding the masses of the atoms in a molecule, we get its molecular weight.

 C6H12O6 molecular mass is 16x1.00+6x12.01+6x16.00= 184.06 g/mol

 Therefore the mass in 6854 mol of C6H12O6 is:

184.06 g/mol x 6854 mol = [tex]1.261x10^{6}[/tex] g

E) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol Cl=35.45 g/mol Co=58.93 g/mol N=14.01 g/mol

By adding the masses of the atoms in a molecule, we get its molecular weight.

 Co(NH3)6 Cl3 molecular mass is 58.93+6x14.01+18x1.00+3x35.45=267.34 g/mol

 Therefore the mass in 2.86 mol of Co(NH3)6 Cl3 is:

267.34 g/mol x 2.86 mol = 764 g