How will the solution of the system y > 2x + 2/3 and y < 2x + 1/3 change if the inequality sign on both inequalities is reversed to y < 2x + 2/3 and y > 2x + 1/3.

Respuesta :

Answer:Infinite solution

Step-by-step explanation:

For Inequalities

[tex]y>2x+\frac{2}{3}[/tex]

3y-6x>2

and [tex]y<2x+\frac{1}{3}[/tex]

3y-6x<1

The required Inequalities have no solution because they do not share the common region for a common solution

But if signs of both inequalities  is changed then the system has infinite number of solution.

[tex]y<2x+\frac{2}{3}[/tex]

3y-6x<2

and [tex]y>2x+\frac{1}{3}[/tex]

3y-6x>1

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Question: How will the solution of the system y > 2x + Two-thirds and y < 2x + One-third change if the inequality sign on both inequalities is reversed to y < 2x + Two-thirds and

y > 2x + One-third?

Sample Response: There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the system has an intersection with an infinite number of solutions.