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The charge entering the positive terminal of an element is q = 5 sin 4 π t mC while the voltage across the element (plus to minus) is v = 3 cos 4 π t V (a) Find the power delivered to the element at t = 0.3 s

Respuesta :

Answer:

123.30 W

Explanation:

We have given q = 5 sin 4πt

And voltage across the element V =  3 cos 4πt

We have to find the power delivered

So [tex]P=Vi=V\frac{dq}{dt}[/tex]

[tex]P=3cos4\pi t\frac{d5sin4\pi t}{dt}[/tex]

[tex]P=60πcos^24\pi t[/tex]

We have to find the power at 0.3 sec

[tex]P=60\pi cos^24\pi 0.3[/tex]

So [tex]P=60\pi cos^2216^{\circ}=123.30W[/tex]

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