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A 30-kg child starts at the center of a playground merry-go-round that has a radius of 2.1 m and rotational inertia of 500 kg⋅m2 and walks out to the edge. The merry-go-round has a rotational speed of 0.20 s−1 when she is at the center?

Respuesta :

Answer:

[tex]\omega = 0.16 s^{-1}[/tex]

Explanation:

As we know that there is no torque on the system of merry go round

so the angular momentum will remain conserved

so here we have

[tex]I_1\omega_0 = (I_1 + I_2)\omega[/tex]

so we will have

[tex]I_1 = 500 kg m^2[/tex]

[tex]I_2 = 30(2.1^2)[/tex]

[tex]I_2 = 132.3 kg m^2[/tex]

[tex]\omega_0 = 0.20 s^{-1}[/tex]

now from above formula

[tex]500(0.20) = (500 + 132.3)\omega[/tex]

[tex]\omega = 0.16 s^{-1}[/tex]

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