Answer:
Acceleration of the meteorite, [tex]a=-38409.09\ m/s^2[/tex]
Explanation:
It is given that,
A Meteorite after striking struck a car, v = 0
Initial speed of the Meteorite, u = 130 m/s
Distance covered by Meteorite, s = 22 cm = 0.22 m
We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :
[tex]a=\dfrac{v^2-u^2}{2s}[/tex]
[tex]a=\dfrac{-(130)^2}{2\times 0.22}[/tex]
[tex]a=-38409.09\ m/s^2[/tex]
So, the deceleration of the Meteorite is [tex]-38409.09\ m/s^2[/tex]. Hence, this is the required solution.
