An automobile travels on a straight road for 40km at 30 km/hr. It then continues in the same director for another 40 km at 60 km/hr. (a) What is the average ... Assume that it moves in the positive x direction.

Respuesta :

Answer:

[tex]v_{avg} = 40 km/h[/tex]

Explanation:

Time taken by the car to move first 40 km distance

[tex]t_1 = \frac{d}{v}[/tex]

here we have

[tex]t_1 = \frac{40}{30}[/tex]

similarly the time taken by car to move next 40 km is given as

[tex]t_2 = \frac{40}{60}[/tex]

so total time of the motion is given as

[tex]t = t_1 + t_2[/tex]

[tex]t = \frac{40}{30} + \frac{40}{60}[/tex]

[tex]t = 2 hours[/tex]

total distance moved by the automobile

[tex]d = 40 + 40 = 80 km[/tex]

so the average speed is given as

[tex]v_{avg} = \frac{distance}{time}[/tex]

[tex]v_{avg} = \frac{80 km}{2 hr}[/tex]

[tex]v_{avg} = 40 km/h[/tex]