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The area of a trapezoid is found with the formula A=
(b
+ b2) h.
A trapezoidal banner has an area of 120 m2 and a height of 10 m. Base 1 (b1)is 16 m shorter than base 2 (b2)
- What are the lengths of the two bases? Let b represent the length of base 1.
Enter your answers in the boxes.
(b1) =_m
(b2) =_m
​

Respuesta :

calculista

Answer:

[tex]b1=4\ m[/tex]

[tex]b2=20\ m[/tex]

Step-by-step explanation:

we know that

The area of a trapezoid is

[tex]A=\frac{1}{2}[b1+b2]h[/tex]

where

b1 and b2 are the parallel bases

h is the height of trapezoid

we have

[tex]A=120\ m^2[/tex]

[tex]h=10\ m[/tex]

[tex]b1=b2-16[/tex]

substitute the values in the formula and solve for b2

[tex]120=\frac{1}{2}[b2-16+b2]10[/tex]

Simplify

[tex]24=[2b2-16][/tex]

[tex]b2=40/2\\b2=20\ m[/tex]

Find the value of b1

[tex]b1=20-16=4\ m[/tex]

therefore

[tex]b1=4\ m[/tex]

[tex]b2=20\ m[/tex]

hannahblonk

Answer:

B1=4cm

Step-by-step explanation:

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