Answer:
8.96 mol of HCl is produced.
Explanation:
CH₄ + 4Cl₂ → CCl₄ + 4HCl 80% yield
CCl₄ + 2HF → CCl₂F₂ + 2HCl 80% yield
The first reaction:
1 mol CH₄ ____ 4 mol HCl 1 mol CH₄ ____ 1 mol CCl₄
2 mol CH₄ ____ x 2 mol CH₄ ____ x
x = 8 mol HCl x = 2 mol HCl
The first reaction would lead to 8 mol of HCl, but as its yield is 80%, the total ammount of HCl produced is 0.8x8 = 6.4 mol HCl
The same applies for CCl₄: 0.8x2 = 1.6 mol CCl₄
The second reaction:
1 mol CCl₄ ____ 2 mol HCl
1.6 mol CH₄ ____ x
x = 3.2 mol HCl
The second reaction would lead to 3.2 mol of HCl, but as its yield is 80%, the total ammount of HCl produced is 0.8x3.2 = 2.56 mol HCl
Therefore, considering both reactions, 8.96 mol of HCl is produced.
