Answer:
The force acting on the passenger is 32072.4 N
Explanation:
It is given that,
Initial speed of the car, u = 28 m/s
Finally, the car comes to rest, v = 0
Distance covered by the car, d = 55 cm = 0.55 m
Mass of the passenger, m = 45 kg
Let a is the acceleration of the car. Using equation of motion as :
[tex]v^2-u^2=2ad[/tex]
[tex]0-u^2=2ad[/tex]
[tex]a=\dfrac{-u^2}{2d}[/tex]
[tex]a=\dfrac{-(28)^2}{2(0.55)}[/tex]
[tex]a=-712.72 m/s^2[/tex]
Let F is the force acting on the passengers. It can be calculated as :
[tex]F=ma[/tex]
[tex]F=45(712.72)[/tex]
F = 32072.4 N
Hence, this is the required solution.
