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The concentration of dye in Solution A is 23.881 M. You have 13 mL of water at your disposal to make the dilutions. The solution is diluted twice, to make Solutions B and C. In the first dilution, 8 parts of Solution A is diluted with 12 parts water to make Solution B. In the second dilution, 9 parts of Solution B is diluted with 4 parts water to make Solution C. What is the concentration of dye in Solution C? Provide your response to three digits after the decimal.

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jufsanabriasa

Answer:

6,613 M

Explanation:

Dilution is the process of reducing the concentration of a solute in solution, mixing initial solution with more solvent.

The concentration of Solution B is:

23,881 M × [tex]\frac{8}{12+8}[/tex] = 9,552 M

Because the initial eight parts are diluted to 12+8 parts.

Thus, concentration of solution C is:

9,552 M × [tex]\frac{9}{4+9}[/tex] = 6,613 M

I hope it helps!

mahima6824soni

The concentration of dye in Solution C is 6.613 M.

What is a solution?

A solution is a mixture of solute into the solvent.

Dilution is the process of lowering a solute's concentration in a solution by mixing it with more solvents.

Given,

The concentration of dye in Solution A is 23.881 M.

Water is 13 ml

8 parts of Solution A is diluted with 12 parts of water

The concentration of solution B is

[tex]\bold{23.881 \times\dfrac{8}{12+8} = 9552 m}[/tex]

Now, The concentration of solution C is

[tex]\bold{9552 m \times\dfrac{9}{4+9} = 6.613\; m}[/tex]

Thus, the concentration of C is 6.613 m.

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https://brainly.com/question/7932885

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