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A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to the potential difference between the plates as they are being separated? A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to the potential difference between the plates as they are being separated? It decreases. It increases. It remains constant. It cannot be determined from the information given.

Respuesta :

Answer:

Potential difference between the plates will increases.

Explanation:

Given that ,first battery charged the capacitor then is removed.

We know that

Capacitance C

[tex]C=\dfrac{A}{4\pi \varepsilon d}[/tex]

[tex]C\alpha \dfrac{1}{ d}[/tex]

And we also know that

Q=C ΔV

ΔV=Q/C

So when distance between plates is increase then it will reduce capacitance(C).It means that for maintaining constant charge on capacitor potential difference will be increase.

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