Answer:
For electron
[tex]V=4.9\times 10^6\ m/s[/tex]
For proton
[tex]V=2680.18\ m/s[/tex]
Explanation:
Given that
E= 564 N/C
Charge on electron
[tex]q=-1.6\times 10^{-19}\ C[/tex]
Mass of electron
[tex]m=9.10\times 10^{-34}\ kg[/tex]
Charge on proton
[tex]q=1.6\times 10^{-19}\ C[/tex]
Mass of proton
[tex]m=1.67\times 10^{-27}\ kg[/tex]
We know that
F = E q
F= m a
For electron:
F= E q
m a = E q
[tex]9.10\times 10^{-34}\ a=564\times 1.6\times 10^{-19}[/tex]
[tex]a=9.9\times 10^{16}\ m/s^2[/tex]
V= U + a t
[tex]V=9.9\times 10^{16}\times 49.6\times 10^{-9}\ m/s[/tex]
[tex]V=4.9\times 10^6\ m/s[/tex]
For proton:
F= E q
m a = E q
[tex]1.67\times 10^{-27}\ a=564\times 1.6\times 10^{-19}[/tex]
[tex]a=5.4\times 10^{10}\ m/s^2[/tex]
V= U + a t
[tex]V=5.4\times 10^{10}\times 49.6\times 10^{-9}\ m/s[/tex]
[tex]V=2680.18\ m/s[/tex]
