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How much total power per area (W/m²) is emitted by a blackbody at 706 K? The Stefan-Boltzmann constant, o, is 5.67 x 10-8 W m-2K-4. Give at least three significant figures. =

Respuesta :

Answer:

E = 14086.460 W/m²

Explanation:

Stefan-Boltzmann's law:

  • E = σ * T∧4

⇒ E = ( 5.67 E-8 W/m².K∧4 ) * ( 706 K )∧4

⇒ E = ( 5.67 E-8 W/m².K∧4 ) * ( 2.484 E11 K∧4 )

⇒ E = 14086.460 W/m²

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