Respuesta :
Explanation:
Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.
It is known that at standard condition, vapor pressure is 760 mm Hg.
And, it is given that methanol vapor pressure in air is 88.5 mm Hg.
Hence, calculate the volume percentage as follows.
Volume percentage = [tex]\frac{\text{given vapor pressure}}{\text{standard vapor pressure}} \times 100[/tex]
= [tex]\frac{88.5}{760} \times 100[/tex]
= 11.65%
Thus, we can conclude that the maximum volume percent of Methanol vapor that can exist at standard conditions is 11.65%.
