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How many grams of NaCl do you need to prepare 200 ml of a 5M solution? The molecular weight of NaCl is 58.4 g/mol. Smol 0.2L-1mol NaCl lib Imol NaClx 8.glol Nacl Mol 58.19 Nac

Respuesta :

joseaaronlara

Answer:

The answer to your question is: 58.4 g of NaCl

Explanation:

Data

Volume = 200 ml = 0.2 l

Concentration = 5M

MW = 58.4 g

mass NaCl = ?

Formula

             Molarity = (# of moles ) / volume

             # of moles = Molarity x volume

             # of moles = 5 x 0.2

             # of moles = 1

              58.4 g ---------------------- 1 mol

              x          ---------------------  1 mol

              x = (1 x 58.4) / 1

             x = 58.4 g of NaCl

samueladesida43

58.4 grams of NaCl is needed to prepare 200 ml of a 5M solution.

HOW TO CALCULATE MASS:

  • The mass of a substance can be calculated by multiplying the number of moles by the molar mass of the substance as follows:

  • Mass of substance = no. of moles × molar mass

  • However, we need to calculate the number of moles in 200 ml of a 5M solution of NaCl by multiplying the molarity by the volume.

  • Volume = 200mL = 0.2L

  • no. of moles of NaCl = 0.2L × 5M

  • no. of moles = 1 mol

  • Molar mass of NaCl is given as 58.4g/mol

  • Mass of NaCl = 1 × 58.4

  • Mass of NaCl = 58.4grams.

  • Therefore, 58.4 grams of NaCl is needed to prepare 200 ml of a 5M solution.

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