Answer:
47.0 N
Explanation:
First of all, let's convert the distance of the rocket from the Sun from AU to metres:
[tex]r = 0.75 AU \cdot 1.5 \cdot 10^{11} =1.13\cdot 10^{11} m[/tex]
The force of gravity acting between the Sun and the rocket is:
[tex]F=G\frac{Mm}{r^2}[/tex]
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}[/tex] is the gravitational constant
[tex]M=2.00\cdot 10^{30} kg[/tex] is the mass of the Sun
m = 4500 kg is the mass of the rocket
r is the distance between the Sun and the rocket
Substituting into the equation,
[tex]F=(6.67\cdot 10^{-11}) \frac{(2.0\cdot 10^{30})(4500)}{(1.13\cdot 10^{11})^2}=47.0 N[/tex]
