Answer:
The magnitude of the electrostatic force is 120.85 N
Explanation:
We can use Coulomb's law to find the electrostatic force between the down quarks.
In scalar form, Coulomb's law states that for charges [tex]q_1[/tex] and [tex]q_2[/tex] separated by a distance d, the magnitude of the electrostatic force F between them is:
[tex]F = k \frac{|q_1q_2|}{d^2}[/tex]
where [tex]k[/tex] is Coulomb's constant.
Taking the values:
[tex]d = 4.6 \ 10^{-15} m[/tex]
[tex]q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}[/tex]
and knowing the value of the Coulomb's constant:
[tex]k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}[/tex]
Taking all this in consideration:
[tex]F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}[/tex]
[tex]F = 120.85 \ N[/tex]
