Answer:
f=5.81 Hz
Explanation:
Given that
m= 0.3 kg
K= 0.4 N/mm
K= 400 N/m
C= 3.28
We know that undamped natural frequency given as
[tex]\omega= \sqrt{\dfrac{K}{m}}[/tex]
Now by putting the values
[tex]\omega= \sqrt{\dfrac{K}{m}}[/tex]
[tex]\omega= \sqrt{\dfrac{400}{0.3}}[/tex]
ω = 36.51 rad/s
We know that
ω = 2 π f
36.51 = 2 x π x f
f=5.81 Hz
So the undamped natural frequency is 5.81 Hz.
