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The chart shows data for a moving object. A 2-column table with 2 rows. The first column is labeled time in seconds with entries 2, 4, 6. Second column is labeled velocity in meters per second with entries 8, 8, 8. Which conclusion is best supported by the information in the chart? The object has negative displacement. The object has negative acceleration. The object does not have displacement. The object is not accelerating.

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skyluke89

Answer:

The object is not accelerating.

Explanation:

We have the following table:

Time (seconds)     2   4   6

Velocity (m/s)        8   8   8

From the table, we notice that the velocity is constant (8 m/s) at any time.

Acceleration is defined as the rate of change of velocity:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

where [tex]\Delta v[/tex] is the change in velocity and [tex]\Delta t[/tex] is the change in time. Since the velocity is constant, [tex]\Delta v=0[/tex] and so [tex]a=0[/tex], which means that the acceleration of the object is zero.

Therefore, the correct answer is

The object is not accelerating.

Answer:

The object is not accelerating.

Explanation:

First, we need to elaborate the chart to see better the correct answer.

t (sec)   v (m/s)

  2            8

  4            8

  6            8

As you can see, no matter the time, the velocity is always the same. We can say that the velocity is constant. Now, the definition of acceleration is the change of velocity, if there's some change in the velocity, there's acceleration, if there isn't any change in the velocity, then there's no acceleration.

In this case, the velocity doesn't change, therefore, the acceleration is null. The object is not accelerating.

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