The sides are:
A=135
B=95
C=130
L=100
W=20
And the perimeter is: 360
Further explanation:
Given that both figures have same parameter
Let P1 be the perimeter of the triangle and P2 be the perimeter of the rectangle
Then
P1=P2
Let the sides of triangle be
A = x+55
B= x+15
C = x+50
and
Sides of rectangle be
L = x+20
W = x
[tex]If\\P_1=P_2\\A+B+C=2L+2W\\(x+55)+(x+15)+(x+50) = 2(x+20)+2x\\x+55+x+15+x+50=2x+40+2x\\3x+120=4x+40\\3x-4x=-120+40\\-x=-80\\x=80\\Now\\A=x+55=80+55=135\\B=x+15=80+15=95\\C=x+50=80+50=130\\L=x+20=80+20=100\\W=x=20\\Now\ we\ have\ to\ calculate\ perimeter\\P_1=A+B+C\\=135+95+130\\=360\\P_2=2L+2W\\=2(100)+2(80)\\=200+160\\=360[/tex]
The sides are:
A=135
B=95
C=130
L=100
W=20
And the perimeter is: 360
Keywords: Perimeter, rectangle, triangle
Learn more about perimeter at:
- brainly.com/question/10772025
- brainly.com/question/10879401
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