Answer:
[tex]-22.7 m/s^2[/tex]
Explanation:
This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the car in this problem,
u = 27.8 m/s
v = 0
s = 17 m
Solving for a, we find the acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-27.8^2}{2(17)}=-22.7 m/s^2[/tex]
