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Let f left parenthesis x comma y right parenthesis equals x squared minus 2 xy minus y squaredf(x,y)=x2−2xy−y2. Compute f left parenthesis 2 comma 0 right parenthesisf(2,0) and f left parenthesis 2 comma negative 3 right parenthesisf(2,−3). f left parenthesis 2 comma 0 right parenthesisf(2,0)equals=nothing​(Simplify your​ answer.) f left parenthesis 2 comma negative 3 right parenthesisf(2,−3)equals=nothing ​(Simplify your​answer.)

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lublana

Answer:

[tex]f(2,0)=4[/tex]

[tex]f(2,-3)=7[/tex]

Step-by-step explanation:

We are given that a function

[tex]f(x,y)=x^2-2xy-y^2[/tex]

a.We have to find the value of f(2,0) and f(2,-3)

Substitute the value x=2 and y=0 then, we get

[tex]f(2,0)=(2)^2-2(2)(0)-0[/tex]

[tex]f(2,0)=4[/tex]

Now, substitute the values x=2 and y=-3 then we get

[tex]f(2,-3)=(2)^2-2(2)(-3)-(-3)^2[/tex]

[tex]f(2,-3)=4+12-9=7[/tex]

[tex]f(2,-3)=7[/tex]

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