A 58.1 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 48.3 kg boy stands at one end of the board. He walks from one end of the board to the other end with a velocity of 1.69 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice? -1.69m/s

Respuesta :

Answer:

V = 1.41 m /s

Explanation:

Movement in both wood board and boy is created by internal forces . No horizontal external force acts on them . So conservation of momentum will apply on both of them for movement in horizontal direction.

Mass of wood board x velocity = mass of boy x velocity

58.1 x V = 48.3 x 1.69

V = 1.41 m /s

The velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 1.41 m/s.

What is conservation of momentum?

Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.

When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

A 58.1 kg wood board is resting on very smooth ice in the middle of a frozen lake.  A 48.3 kg boy stands at one end of the board.

The boy walks from one end of the board to the other end with a velocity of 1.69 m/s relative to the ice in the positive direction. Thus, by the conservation of momentum,

[tex]m_{board}\times V_1=m_{boy}\times V_2\\58.1\times V_1=48.3\times 1.69\\V_{1}=1.41\rm\; m/s[/tex]

Thus, the velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 1.41 m/s.

Learn more about the conservation of momentum here;

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