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Answer:

see explanation

Step-by-step explanation:

Given the n th term formula.

To find the first 3 terms substitute n = 1, 2, 3 into the formula

(a)

[tex]a_{1}[/tex] = (3 × 1) + 2 = 3 + 2 = 5

[tex]a_{2}[/tex] = (3 × 2) + 2 = 6 + 2 = 8

[tex]a_{3}[/tex] = (3 × 3) + 2 = 9 + 2 = 11

The first three terms are 5, 8, 11

(b)

Substitute n = 10 into the formula

[tex]a_{10}[/tex] = (3 × 10) + 2 = 30 + 2 = 32

The tenth term is 32

MrRoyal

An arithmetic sequence is a set of numbers with a common difference.

  • The first three terms are 4, 7 and 10
  • The tenth term is 31

Given

[tex]T_n = 3n + 1[/tex]

The first three terms

When [tex]n = 1[/tex]

[tex]T_1 = 3 \times 1 + 1 = 4[/tex]

When [tex]n = 2[/tex]

[tex]T_2 = 3 \times 2 + 1 = 7[/tex]

When [tex]n = 3[/tex]

[tex]T_3 = 3 \times 3 + 1 = 10[/tex]

So, the first three terms are 4, 7 and 10

The tenth term

When [tex]n = 10[/tex], we have:

[tex]T_{10} = 3 \times 10 + 1[/tex]

[tex]T_{10} = 30 + 1[/tex]

[tex]T_{10} = 31[/tex]

Hence, the tenth term is 31

Read more about sequence at:

https://brainly.com/question/18109692

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