Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 4x - 1 ← is in slope- intercept form
with slope m = - 4
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-4}[/tex] = [tex]\frac{1}{4}[/tex], thus
y = [tex]\frac{1}{4}[/tex] x + c ← is the partial equation of the line
To find c substitute (- 2, 2) into the partial equation
2 = - [tex]\frac{1}{2}[/tex] + c ⇒ c = [tex]\frac{5}{2}[/tex]
y = [tex]\frac{1}{4}[/tex] x + [tex]\frac{5}{2}[/tex] ← in slope- intercept form
