A data analyst has spreadsheets numbered

1

,

2

, databases numbered

1

,

2

,

3

, and presentations numbered

1

,

2

,

3

,

4

to work on this week. If a single item is picked at random to work on, what is the probability that the item is a database AND has an odd number?


Provide the final answer as a fraction. PLEASE HELP ASAP!

Respuesta :

Answer:

[tex]\frac{2}{9}[/tex]

Step-by-step explanation:

[tex]{\textrm}{Total number of objects here} = 9[/tex]

(2 spreadsheets, 3 databases and 4 presentations,

[tex]{\textrm}({Total} = 2+3+4 = 9)[/tex]

[tex]{\textrm}{No. of databases with an odd number} = 2 {\textrm}{(databases with number 1 and 3})[/tex]

As  not mentioned other wise equal chances of all the outcomes is assumed so, by the classical definition of probability,

P(The chosen item is a odd numbered database)

=[tex]\frac{2}{9}[/tex]