Respuesta :

Funkeheart

Answer:

[tex] kmno4 = 0\\ k(potassium) = + 1 \\ mn(manganese) = x\\ o(oxygen) = - 2 \\ \\ (+ 1) + x + ( - 2)4 = 0 \\ 1 + x - 8 = 0 \\ x = + 8 - 1 \\ x = + 7[/tex]

nandhini123

The oxidation number of Mn in [tex]KMnO_4[/tex]  is +7.

Explanation:

In a compound  the sum of the oxidation states of all the atoms will be to equal the total charge on the ions.

[tex]KMnO_4[/tex] is neutral hence its total charge is zero

Oxidation number of  potassium+ Oxidation number of Manganese+Oxidation number of  Oxygen=0

We Know that

Oxidation number of  potassium= +1

Oxidation number of  Oxygen=  -2

 Substituting the values,

(+1)+ Oxidation number of  Manganese+ 4(-2)=0

(+1)+ Oxidation number of  Manganese+ (-8)=0

(-7)+ Oxidation number of  Manganese=0

Oxidation number of  Manganese= +7

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