The bomb takes 55.33 seconds to reach its target on the ground
Step-by-step explanation:
The formula of the height of a free fall object is
h = ut + [tex]\frac{1}{2}[/tex] g t², where
1. h is the vertical distance
2. u is the initial speed of the object
3. t is the time of the object's trip
4. g is the acceleration of gravity
A plane with an altitude of 15000 meters drops a bomb
We need to find how long it takes to reach its target on the ground
∵ The altitude of the plane is 15000 meters
∴ h = 15000 m
∵ The bomb is dropped ⇒ initial velocity is 0
∴ u = 0 m/s
∵ g = 9.8 m/s²
- Substitute these values in the formula above
∴ 15000 = (0)t + [tex]\frac{1}{2}[/tex] (9.8) t²
∴ 15000 = 4.9 t²
- Divide both sides by 4.9
∴ t² = 3061.22
- Take √ for both sides
∴ t = 55.33 seconds
The bomb takes 55.33 seconds to reach its target on the ground
Learn more
You can learn more about the rules of projectile motion in brainly.com/question/6902645
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