Answer:
11m/s
Explanation:
[tex]v = v0 + a \times t[/tex]
where...
v is current velocity
v0 is starting velocity
a is constant acceleration
and t is time accelerating
plugging in given values gives us
v = 5+.6*10 = 5+6 = 11
therefore the velocity at the end of 10 seconds is 11m/s
