Answer:
[tex]x=\sqrt[4]{\dfrac{y+16s^3}{s}}[/tex]
Step-by-step explanation:
It appears you intend your equation to be ...
[tex]y=sx^4-16s^3[/tex]
In any "solve for" situation, it helps to consider what is being done to the variable of interest. (The order of operations is useful here.) In this case, ...
You can isolate the variable by "undoing" these operations in reverse order.
The subtraction of 16s³ can be undone by adding 16s³. Anything we do must be done to both sides of the equation, so this gives ...
[tex]y+16s^3=sx^4 \qquad\text{add $16s^3$}\\\\\dfrac{y+16s^3}{s}=x^4 \qquad\text{divide by the coefficient of the x-term}\\\\\sqrt[4]{\dfrac{y+16s^3}{s}}=x \qquad\text{take the fourth root to undo the power}[/tex]
