Answer:
the three consecutive odd integers are 9, 11, and 13.
Step-by-step explanation:
Let's say that the first odd integer is x. The second consecutive odd integer would have to be x+2. (It would not be x+1 because that would result in an even integer. The sum of any two odd numbers is even.) The third consecutive odd integer would be (x+2) +2 or x+4.
The sum of the first, twice the second, and three times the third can be written as:
x+2(x+2)+3(x+4)
This equals 70. We can now distribute and solve for x:
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70(distribute)
6x+16=70(combine like terms)
6x=54(subtract 16 from both sides)
x=9(divide by 9)
Thus, the three consecutive odd integers are 9, 11, and 13
hope this helps :)
