Answer:
[tex]y\leq -\frac{1}{3}x+1[/tex]
Step-by-step explanation:
Given:
From the graph, the x and y intercepts are at the points (3, 0) and (0, 1) respectively.
Now, for a line with two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex], the slope is given as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Here, [tex](x_1,y_1)=(3,0)\ and\ (x_2,y_2)=(0,1)[/tex]. Therefore,
[tex]m=\frac{1-0}{0-3}=-\frac{1}{3}[/tex]
Now, y-intercept is [tex]b=1[/tex]
Therefore, the standard form of a line is of the form: [tex]y=mx+b[/tex]. So, the equation of the line on the graph is:
[tex]y=-\frac{1}{3}x+1[/tex]
Now, from the graph, the region is below the line including all the points on the line. Therefore, the inequality used is less than or equal to. This gives,
[tex]y\leq -\frac{1}{3}x+1[/tex]
