Answer:
(5,6) , (5,-2)
Step-by-step explanation:
Let the required point be P(5,y).
Its distance from (2,2) is 5 units.
So, [tex](5-2)^{2}[/tex] + [tex](y-2)^{2}[/tex] = 25.
So, [tex]3^{2}[/tex] + [tex](y-2)^{2}[/tex] = 25.
9 + [tex](y-2)^{2}[/tex] = 25.
[tex](y-2)^{2}[/tex] = 16
Two cases are possible for now
case 1 : y-2 = 4 .
y = 6
required point will be (5,6)
case 2 : y - 2 = -4.
y = -2.
required point will be (5,-2).
Two points are possible : (5,6) , (5,-2).
