Answer:
Force per unit length between two conductors will be [tex]3.2\times 10^{-4}N[/tex]
Explanation:
We have given that two long parallel wires each carrying a current of 12 A
So [tex]I_1=I_2=12A[/tex]
Distance between the two conductors d = 9 cm = 0.09 m
We know that magnetic force between two parallel conductors per unit length is given by
[tex]F=\frac{\mu _0I_1I_2}{2\pi d}=\frac{4\times 3.14\times 10^{-7}\times 12\times 12}{2\times 3.14\times 0.09}=3.2\times 10^{-4}N[/tex]
Force per unit length between two conductors will be [tex]3.2\times 10^{-4}N[/tex]
