A movie theater has a seating capacity of 383. The theater charges $5.00 for children, $7.00 for students, and $12.00 of
adults. There are half as many adults as there are children. If the total ticket sales was $ 2778, How many children,
students, and adults attended?

Respuesta :

194 children, 92 students, and 97 adults attended

Step-by-step explanation:

The given is:

  • A movie theater has a seating capacity of 383
  • The theater charges $5 for children, $7 for students, and $12 for adults
  • There are half as many adults as there are children
  • The total ticket sales was $ 2778

We need to find how many children,

students, and adults attended

Assume that x represents the number of children, y represents the number of students, and z represents the number of adults

∵ There were x children, y students and z adult attended

∵ The movie theater has a seating capacity of 383

x + y + z = 383 ⇒ (1)

∵ The theater charges $5 for children, $7 for students, and

   $12 for adults

∵ The total ticket sales was $2778

5x + 7y + 12z = 2778 ⇒ (2)

∵ There are half as many adults as there are children

- Half means 0.5

z = 0.5x ⇒ (3)

Substitute equation (3) in equations (1) and (2)

∵ x + y + 0.5x = 383

- Add like terms

1.5x + y = 383 ⇒ (4)

∵ 5x + 7y + 12(0.5x) = 2778

∴ 5x + 7y + 6x = 2778

- Add like terms

11x + 7y = 2778 ⇒ (5)

Let us solve equations (4) and (5) to find x and y

Multiply equation (4) by -7 to eliminate y

-10.5x - 7y = -2681 ⇒ (6)

- Add equations (5) and (6)

∴ 0.5x = 97

- Divide both sides by 0.5

x = 194

Substitute the value of x in equations (4) and (3) to find y and z

∵ 1.5(194) + y = 383

∴ 291 + y = 383

- Subtract 291 from both sides

y = 92

∵ z = 0.5 (194)

z = 97

194 children, 92 students, and 97 adults attended

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You can learn more about the system of linear equations in brainly.com/question/6075514

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