Answer: The value of equilibrium constant for the above equation is 36
Explanation:
We are given:
Initial moles of X = 4.00 moles
Initial moles of Y = 4.00 moles
Equilibrium moles of Z = 6.00 moles
Volume of vessel = 1.00 L
Initial concentration of X = [tex]\frac{4}{1}=4[/tex]
Initial concentration of Y = [tex]\frac{4}{1}=4[/tex]
Equilibrium concentration of Z = [tex]\frac{6}{1}=6[/tex]
The given chemical equation follows:
[tex]X(g)+Y(g)\rightarrow 2Z(g)[/tex]
Initial: 4 4
At eqllm: 4-x 4-x 2x
Calculating for 'x', we get:
[tex]\Rightarrow 2x=6\\\\\Rightarrow x=3[/tex]
The expression of [tex]K_c[/tex] for above equation follows:
[tex]K_c=\frac{[Z]^2}{[X]\times [Y]}[/tex]
Putting values in above equation, we get:
[tex]K_c=\frac{6^2}{1\times 1}\\\\K_c=36[/tex]
Hence, the value of equilibrium constant for the above equation is 36
