Respuesta :
Answer:
The pipe C alone can fill the tank in 14 hours .
Step-by-step explanation:
Given as :
The three pipes a , b , c can fill the pipes in 6 hours
They work for 2 hours
After that c pipe is close and a , b finish remaining work
Now, According to question
In 1 hour pipes ( a + b + c ) fill [tex]\frac{1}{6}[/tex] of the tank
∴ In 2 hour pipes ( a + b + c ) fill [tex]\frac{2}{6}[/tex] = [tex]\frac{1}{3}[/tex] of the tank
Remaining ( 1 - [tex]\frac{1}{3}[/tex] ) = [tex]\frac{2}{3}[/tex] part is filled by pipes a and b in 7 hours
∴ The whole tank is filled by a and b in 7 × [tex]\frac{3}{2}[/tex] = [tex]\frac{21}{2}[/tex] hours
∴ In 1 hour pipes A and b fill the tank in [tex]\frac{2}{21}[/tex] hours
∴ In 1 hour pipes C alone can fill the tank in[tex]\frac{1}{6}[/tex] - [tex]\frac{2}{21}[/tex] hours
Or, In 1 hour pipes C alone can fill the tank in [tex]\frac{9}{126}[/tex] = [tex]\frac{1}{14}[/tex]
Or, In 1 hour pipes C alone can fill the tank in 14 hours
Hence The pipe C alone can fill the tank in 14 hours . Answer
