Russell drags his suitcase 15.0 M from the door of his house to the car at a constant speed with a horizontal force of 95.0 N. How much work does Russell do to overcome the force of

Respuesta :

The work done is 1425 J

Explanation:

The work done by a force to move an object is given by

[tex]W=Fd cos \theta[/tex]

where

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

For the suitcase in this problem, we have:

F = 95.0 N is the force applied

d = 15.0 m is the displacement

[tex]\theta=0[/tex], since the force is parallel to the displacement

Substituting, we find

[tex]W=(95.0)(15.0)(cos 0)=1425 J[/tex]

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