Answer:
The phase angle is 0.0180 rad.
(c) is correct option.
Explanation:
Given that,
Voltage = 12 V
Angular velocity = 50 Hz
Capacitance [tex]C= 20\times10^{-2}\ F[/tex]
Inductance [tex]L=20\times10^{-3}\ H[/tex]
Resistance [tex]R= 50\ Omega[/tex]
We need to calculate the impedance
Using formula of impedance
[tex]z=\sqrt{R^2+(\omega L-\dfrac{1}{\omega C})^2}[/tex]
[tex]z=\sqrt{50^2+(50\times20\times10^{-3}-\dfrac{1}{50\times20\times10^{-2}})^2}[/tex]
[tex]z=50.00[/tex]
We need to calculate the phase angle
Using formula of phase angle
[tex]\theta=\cos^{-1}(\dfrac{R}{z})[/tex]
[tex]\theta=\cos^{-1}(\dfrac{50}{50.00})[/tex]
[tex]\theta=0.0180\ rad[/tex]
Hence, The phase angle is 0.0180 rad.
