1) The acceleration of the plane is 1.89 times the acceleration of gravity
2) The force acting on the airplane is [tex]2.22\cdot 10^5 N[/tex]
Explanation:
1)
The acceleration of the plane is given by
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final velocity of the plane
u is the initial velocity
t is the time elapsed
For the airplane in this problem, we have:
[tex]u=0[/tex] (it starts from rest)
[tex]v=200 km/h \cdot \frac{1000 m/km}{3600 s/h}=55.6 m/s[/tex] is the final velocity
[tex]t=3 s[/tex] is the time
Substituting, we find
[tex]a=\frac{55.6-0}{3}=18.5 m/s^2[/tex]
The acceleration of gravity is
[tex]g=9.8 m/s^2[/tex]
So, the acceleration of the plane relative to [tex]g[/tex] is
[tex]\frac{a}{g}=\frac{18.5}{9.8}=1.89[/tex]
2)
The average force exerted on the plane is given by Newton's second law:
[tex]F=ma[/tex]
where
F is the force
m is the mass of the airplane
a is the acceleration
In this problem, we have
[tex]m=12000 kg[/tex] is the mass of the plane
[tex]a=18.5 m/s^2[/tex] is the acceleration
Substituting, we find:
[tex]F=(12000)(18.5)=2.22\cdot 10^5 N[/tex]
Learn more about acceleration and forces:
brainly.com/question/11411375
brainly.com/question/1971321
brainly.com/question/2286502
brainly.com/question/2562700
#LearnwithBrainly
