.The sum of the digits of a two-digit number is one-fifth the value of the
number. The tens digits is one less than the ones digit. What is the two-digit
number? (Hint: Assign a different variable to the value of each digit.)

Respuesta :

Padoru

Here's how I'm assigning a different variable to the value of each digit:

10x + y, where x is the first digit, and y is the second digit (you can test if this equation works)

The sum of the digits is 1/5 the value of the number. Using the information, we can form the equation:

x + y = (1/5)(10x + y)

Simplify

x + y = 2x + (1/5)y

The tens digit is one less than the ones digit. Using this information, we can form the equation:

x = y - 1

Adding both sides by 1 gives

x + 1 = y

Substituting this into the y's the first equation gives:

x + x + 1 = 2x + (1/5)(x + 1)

Distribute and simplify

2x + 1 = 2x + (1/5)x + 1/5

Subtract both sides by 2x

1 = (1/5)x + 1/5

Subtract 1/5 from both sides

4/5 = (1/5)x

Multiply both sides by 5

4 = x

x = 4

Use this to solve for y

x + 1 = y

4 + 1 = y

y = 5

Thus, x = 4 and y = 5. The 2 digit number is XY, which is 45.

Let me know if you need any clarifications; this was a very interesting math problem to solve!