Answer:
[tex] 2b+f = 8[/tex] (1)
[tex]3b+f=11[/tex] (2)
[tex] b = 11-8=3[/tex]
[tex]f= 8-2(3) = 8-6 =2[/tex]
Step-by-step explanation:
For this case we can put some notation
Let b= dozen bagels and f= delivery fee
And for this case we know that "On Monday, they delivered two dozen bagels, b, to an office at a total cost of $8", so then the total taling in count the delivery fee we have this:
[tex] 2b+f = 8[/tex]
And for the other part "On Tuesday, three dozen bagels were delivered at a total cost of $11", we can write the expression like this:
[tex]3b+f=11[/tex]
And our system of equations would be:
[tex] 2b+f = 8[/tex] (1)
[tex]3b+f=11[/tex] (2)
If we solve for f from equation (1) we got:
[tex]f= 8-2b[/tex]
And if w replace this into equation (2) we got:
[tex]3b+8-2b=11[/tex]
[tex] b = 11-8=3[/tex]
And solving for f we got:
[tex]f= 8-2(3) = 8-6 =2[/tex]
