2 times the volume of cylinder Q is equal to the volume of cylinder P
Solution:
The volume of right circular cylinder is given as:
[tex]V = \pi r^2 h[/tex]
Where "r" is the radius and "h" is the height of cylinder
The height of right circular cylinder P is twice the height of right circular cylinder Q
Let "h" be the height of cylinder p and "H" be the height of cylinder Q
Height of cylinder P = 2 (height of right circular cylinder Q)
h = 2H ---- eqn 1
The radius of the cylinders are of equal length
Let "r" be the radius of cylinder P and cylinder Q
Volume of cylinder Q:
[tex]V_Q = \pi r^2H[/tex]
Volume of cylinder P:
[tex]V_P = \pi r^2h[/tex]
Substitute eqn 1
[tex]V_P = \pi r^2 (2H)\\\\V_P = 2 \pi r^2 H[/tex]
Therefore,
[tex]V_P = 2(\pi r^2 H)\\\\V_P = 2(V_Q)[/tex]
Volume of cylinder P = 2(volume of cylinder Q)
There 2 times the volume of cylinder Q is equal to the volume of cylinder P
