Answer:
P_p = 27000 psf
Explanation:
given,
height of the retaining wall = h = 12 ft
internal angle of friction (∅)= 30°
unit weight = 125 pcf
Rankine passive earth pressure = ?
k_p is the coefficient of passive earth pressure
[tex]k_p = \dfrac{1 + sin\phi}{1 - sin\phi}[/tex]
[tex]k_p = \dfrac{1 + sin30^0}{1 - sin30^0}[/tex]
k_p = 3
Passive earth pressure
[tex]P_p = \dfrac{1}{2}k_p \gamma H^2[/tex]
[tex]P_p = \dfrac{1}{2}\times 3\times 125 \times 12^2[/tex]
P_p = 27000 psf
Rankine passive earth pressure on the wall is equal to P_p = 27000 psf
