Respuesta :
Answer:
v = 51.36 m/s
Explanation:
given,
mass of the car = 805 Kg
circumference of the track = 4.25 Km
Force on the car in circular path, F = 3140 N
tangential speed of the car = ?
2 π r = 4250
r = 676.4 m
using formula
[tex]F = \dfrac{mv^2}{r}[/tex]
[tex]3140 = \dfrac{805\times v^2}{676.4}[/tex]
v² = 2638.38
v = 51.36 m/s
hence, tangential speed of the car is equal to 51.36 m/s
