Answer:
(c) 43.
Step-by-step explanation:
Given:
Margin of error (E) = 2
Sample variance [tex](s^{2})[/tex] = 44
Confidence level = 95%
The z- value at 95% confidence level is 1.96.
The sample using the provided information can be calculated as:
[tex]n=(\frac{z(s)}{E})^{2} \\n=\frac{z^{2} s^{2} }{E^{2} } \\n=\frac{1.96^{2} (44) }{2^{2} }\\n= 42.52\\n=43[/tex]
Hence, the correct option is (c) 43.
