Answer:
Molality = 7.5 mol/kg
Explanation:
Given data:
Mass of NH₄Cl = 6.30 g
Mass of water = 15.7 g (15.7/1000 =0.016 kg)
Molality = ?
Solution:
Formula of molality:
Molality = Moles of solute / mass of solvent in gram
Now we will first calculate the number of moles of solute( NH₄Cl )
Number of moles = mass/ molar mass
Molar mass of NH₄Cl = 53.491 g/mol
Number of moles = 6.30 g/ 53.491 g/mol
Number of moles = 0.12 mol
Now we will calculate the molality.
Molality = Moles of solute / mass of solvent in gram
Molality = 0.12 mol / 0.016 kg
Molality = 7.5 m
or (m=mol/kg)
Molality = 7.5 mol/kg
Quantification of moles of a solute in a solution of a kilogram of a solvent is called molality.
The correct answer is:
The molality of the NH₄Cl is 7.5 mol/kg
This can be calculated as:
[tex]\dfrac{15.7}{1000}&= 0.016 \;\text{kg}[/tex]
Molality can be calculated by:
[tex]\text{Molality} &= \dfrac{\text{Moles of solute}}{\text{Mass of solvent in kg or 1000 g}}[/tex]
To calculate the number of moles of solute ( NH₄Cl ):
[tex]\text{Number of moles} & = \dfrac{\text{Mass}}{\text{Molar mass}}[/tex]
Molar mass of NH₄Cl = 53.491 g/mol
[tex]\text{Number of moles} & = \dfrac{\text{6.30 g}}{\text{53.491 g/mol}} & = 0.12 \; \text{mol}[/tex]
Now, molality can be calculated:
[tex]\text{Molality} &= \dfrac{\text{0.12 mol}}{\text{0.016 kg}}[/tex]
Molality = 7.5 m
Therefore, the Molality of solute of NH₄Cl = 7.5 mol/kg.
To learn more about molality refer to the link:
https://brainly.com/question/15490677
