Answer: 1.15
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Work Shown:
QR = 73
QP = 55
PR = x
Pythagorean Theorem
a^2 + b^2 = c^2
(QP)^2 + (PR)^2 = (QR)^2
(55)^2 + (x)^2 = (73)^2
3025 + x^2 = 5329
x^2 = 5329-3025
x^2 = 2304
x = sqrt(2304)
x = 48
PR = 48
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tan(angle) = opposite/adjacent
tan(R) = QP/PR
tan(R) = 55/48
tan(R) = 1.1458333 approximately
tan(R) = 1.15
