Answer:
Part 1) [tex]sin(\theta)=0.60[/tex]
Part 2) [tex]cos(\theta)=0.80[/tex]
Step-by-step explanation:
Let
A(9.31, 7.02)
see the attached figure to better understand the problem
step 1
Find the value of r (hypotenuse of the right triangle)
Applying the Pythagorean Theorem
[tex]r^2=x^2+y^2[/tex]
[tex]r^2=9.31^2+7.02^2\\r^2=135.9565\\r=11.66[/tex]
step 2
Find the value of sin(θ)
In the right triangle of the figure
[tex]sin(\theta)=\frac{y}{r}[/tex] ----> by SOH (opposite side divided by the hypotenuse)
substitute
[tex]sin(\theta)=\frac{7.02}{11.66}=0.60[/tex]
Is positive because lie in the First Quadrant
step 3
Find the value of cos(θ)
In the right triangle of the figure
[tex]cos(\theta)=\frac{x}{r}[/tex] ----> by CAH (adjacent side divided by the hypotenuse)
substitute
[tex]cos(\theta)=\frac{9.31}{11.66}=0.80[/tex]
Is positive because lie in the First Quadrant
